Optimal. Leaf size=213 \[ \frac{4 a^3 (11 A+21 C) \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{21 d}+\frac{4 a^3 (17 A+27 C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{8 a^3 (16 A+21 C) \sin (c+d x) \sqrt{\cos (c+d x)}}{105 d}+\frac{2 (73 A+63 C) \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^3 \cos (c+d x)+a^3\right )}{315 d}+\frac{4 A \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^2 \cos (c+d x)+a^2\right )^2}{21 a d}+\frac{2 A \sin (c+d x) \sqrt{\cos (c+d x)} (a \cos (c+d x)+a)^3}{9 d} \]
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Rubi [A] time = 0.622529, antiderivative size = 213, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.229, Rules used = {4114, 3046, 2976, 2968, 3023, 2748, 2641, 2639} \[ \frac{4 a^3 (11 A+21 C) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{4 a^3 (17 A+27 C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{8 a^3 (16 A+21 C) \sin (c+d x) \sqrt{\cos (c+d x)}}{105 d}+\frac{2 (73 A+63 C) \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^3 \cos (c+d x)+a^3\right )}{315 d}+\frac{4 A \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^2 \cos (c+d x)+a^2\right )^2}{21 a d}+\frac{2 A \sin (c+d x) \sqrt{\cos (c+d x)} (a \cos (c+d x)+a)^3}{9 d} \]
Antiderivative was successfully verified.
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Rule 4114
Rule 3046
Rule 2976
Rule 2968
Rule 3023
Rule 2748
Rule 2641
Rule 2639
Rubi steps
\begin{align*} \int \cos ^{\frac{9}{2}}(c+d x) (a+a \sec (c+d x))^3 \left (A+C \sec ^2(c+d x)\right ) \, dx &=\int \frac{(a+a \cos (c+d x))^3 \left (C+A \cos ^2(c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{2 \int \frac{(a+a \cos (c+d x))^3 \left (\frac{1}{2} a (A+9 C)+3 a A \cos (c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx}{9 a}\\ &=\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{4 \int \frac{(a+a \cos (c+d x))^2 \left (\frac{1}{4} a^2 (13 A+63 C)+\frac{1}{4} a^2 (73 A+63 C) \cos (c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx}{63 a}\\ &=\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{2 (73 A+63 C) \sqrt{\cos (c+d x)} \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{315 d}+\frac{8 \int \frac{(a+a \cos (c+d x)) \left (\frac{3}{4} a^3 (23 A+63 C)+\frac{9}{2} a^3 (16 A+21 C) \cos (c+d x)\right )}{\sqrt{\cos (c+d x)}} \, dx}{315 a}\\ &=\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{2 (73 A+63 C) \sqrt{\cos (c+d x)} \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{315 d}+\frac{8 \int \frac{\frac{3}{4} a^4 (23 A+63 C)+\left (\frac{9}{2} a^4 (16 A+21 C)+\frac{3}{4} a^4 (23 A+63 C)\right ) \cos (c+d x)+\frac{9}{2} a^4 (16 A+21 C) \cos ^2(c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{315 a}\\ &=\frac{8 a^3 (16 A+21 C) \sqrt{\cos (c+d x)} \sin (c+d x)}{105 d}+\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{2 (73 A+63 C) \sqrt{\cos (c+d x)} \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{315 d}+\frac{16 \int \frac{\frac{45}{8} a^4 (11 A+21 C)+\frac{63}{8} a^4 (17 A+27 C) \cos (c+d x)}{\sqrt{\cos (c+d x)}} \, dx}{945 a}\\ &=\frac{8 a^3 (16 A+21 C) \sqrt{\cos (c+d x)} \sin (c+d x)}{105 d}+\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{2 (73 A+63 C) \sqrt{\cos (c+d x)} \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{315 d}+\frac{1}{21} \left (2 a^3 (11 A+21 C)\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx+\frac{1}{15} \left (2 a^3 (17 A+27 C)\right ) \int \sqrt{\cos (c+d x)} \, dx\\ &=\frac{4 a^3 (17 A+27 C) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{4 a^3 (11 A+21 C) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{8 a^3 (16 A+21 C) \sqrt{\cos (c+d x)} \sin (c+d x)}{105 d}+\frac{2 A \sqrt{\cos (c+d x)} (a+a \cos (c+d x))^3 \sin (c+d x)}{9 d}+\frac{4 A \sqrt{\cos (c+d x)} \left (a^2+a^2 \cos (c+d x)\right )^2 \sin (c+d x)}{21 a d}+\frac{2 (73 A+63 C) \sqrt{\cos (c+d x)} \left (a^3+a^3 \cos (c+d x)\right ) \sin (c+d x)}{315 d}\\ \end{align*}
Mathematica [C] time = 6.43928, size = 1116, normalized size = 5.24 \[ \text{result too large to display} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 2.142, size = 408, normalized size = 1.9 \begin{align*} -{\frac{4\,{a}^{3}}{315\,d}\sqrt{ \left ( 2\, \left ( \cos \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1 \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}} \left ( -560\,A\cos \left ( 1/2\,dx+c/2 \right ) \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{10}+2200\,A \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{8}\cos \left ( 1/2\,dx+c/2 \right ) + \left ( -3412\,A-252\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{6}\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) + \left ( 2702\,A+882\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{4}\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) + \left ( -738\,A-378\,C \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +165\,A\sqrt{ \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) -357\,A\sqrt{ \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}{\it EllipticE} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) +315\,C\sqrt{ \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) -567\,C\sqrt{ \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}{\it EllipticE} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) \right ){\frac{1}{\sqrt{-2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{4}+ \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}}}} \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{2\, \left ( \cos \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (C a^{3} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{5} + 3 \, C a^{3} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{4} +{\left (A + 3 \, C\right )} a^{3} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{3} +{\left (3 \, A + C\right )} a^{3} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{2} + 3 \, A a^{3} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right ) + A a^{3} \cos \left (d x + c\right )^{4}\right )} \sqrt{\cos \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \sec \left (d x + c\right )^{2} + A\right )}{\left (a \sec \left (d x + c\right ) + a\right )}^{3} \cos \left (d x + c\right )^{\frac{9}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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